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(1.14*10^-3)x-1.48*10^-4=x
We move all terms to the left:
(1.14*10^-3)x-1.48*10^-4-(x)=0
We add all the numbers together, and all the variables
-1x+(1.14*10^-3)x=0
We multiply parentheses
11.4x^2-1x-3x=0
We add all the numbers together, and all the variables
11.4x^2-4x=0
a = 11.4; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·11.4·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*11.4}=\frac{0}{22.8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*11.4}=\frac{8}{22.8} =4/11.4 $
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